Mass Transfer Cengel 5th Edition Chapter 3 | Solution Manual Heat And

$\dot{Q} {conv}=\dot{Q} {net}-\dot{Q} {rad}-\dot{Q} {evap}$

$h=\frac{\dot{Q} {conv}}{A(T {skin}-T_{\infty})}=\frac{108.1}{1.5 \times (32-20)}=3.01W/m^{2}K$

$\dot{Q}_{rad}=1 \times 5.67 \times 10^{-8} \times 1.5 \times (305^{4}-293^{4})=41.9W$

Solution:

$\dot{Q}=10 \times \pi \times 0.08 \times 5 \times (150-20)=3719W$

Solution:

$Nu_{D}=0.26 \times (6.14 \times 10^{6})^{0.6} \times (7.56)^{0.35}=2152.5$